Ajax Dropdown Menu it's make easy for user to use interface. When you choose first dropdown menu data in second dropdown will be filter and data related in first dropdown will be show automatic
For This Example Code is PHP and Database is MySQL
Example : Stated and Cities
1. Create Dropdown Menu (state_dropdown.php)
<?
echo "<form name=sel>\n";
echo "States : <font id=states><select>\n";
echo "<option value='0'>============</option> \n" ;
echo "</select></font>\n";
echo "Cities : <font id=cities><select>\n";
echo "<option value='0'>=== none ===</option> \n" ;
echo "</select></font>\n";
?>
<script language=Javascript>
function Inint_AJAX() {
try { return new ActiveXObject("Msxml2.XMLHTTP"); } catch(e) {} //IE
try { return new ActiveXObject("Microsoft.XMLHTTP"); } catch(e) {} //IE
try { return new XMLHttpRequest(); } catch(e) {} //Native Javascript
alert("XMLHttpRequest not supported");
return null;
};
function dochange(src, val) {
var req = Inint_AJAX();
req.onreadystatechange = function () {
if (req.readyState==4) {
if (req.status==200) {
document.getElementById(src).innerHTML=req.responseText; //retuen value
}
}
};
req.open("GET", "state.php?data="+src+"&val="+val); //make connection
req.setRequestHeader("Content-Type", "application/x-www-form-urlencoded;charset=iso-8859-1"); // set Header
req.send(null); //send value
}
window.onLoad=dochange('states', -1); // value in first dropdown
</script>
2. Select States and Cities to Show in Dropdown (state.php)
<?
//set IE read from page only not read from cache
header ("Expires: Mon, 26 Jul 1997 05:00:00 GMT");
header ("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT");
header ("Cache-Control: no-cache, must-revalidate");
header ("Pragma: no-cache");
header("content-type: application/x-javascript; charset=tis-620");
$data=$_GET['data'];
$val=$_GET['val'];
//set database
$dbhost = "localhost";
$dbuser = "";
$dbpass = "";
$dbname = "test";
mysql_pconnect($dbhost,$dbuser,$dbpass) or die ("Unable to connect to MySQL server");
if ($data=='states') { // first dropdown
echo "<select name='states' onChange=\"dochange('cities', this.value)\">\n";
echo "<option value='0'>==== choose state ====</option>\n";
$result=mysql_db_query($dbname,"select `id`, `state` from states order by `state`");
while(list($id, $name)=mysql_fetch_array($result)){
echo "<option value=\"$id\" >$name</option> \n" ;
}
} else if ($data=='cities') { // second dropdown
echo "<select name='cities' >\n";
echo "<option value='0'>====choose cities ====</option>\n";
$result=mysql_db_query($dbname,"SELECT `id`, `city` FROM cities WHERE `state_id` = '$val' ORDER BY `city` ");
while(list($id, $name)=mysql_fetch_array($result)){
echo "<option value=\"$id\" >$name</option> \n" ;
}
}
echo "</select>\n";
?>


See Example : States and Cities DropDown
Download Source code : ajax_dropdown.rar
mirror : ajax_dropdown.rar
( Please don’t directly link to the file… thank you )
Example 2 : This is Triple Ajax Dropdown Menu - Province - Ampher - Tumbon in Thailand
1. Create Dropdown Menu (locale_dropdown.php)
<? echo "<form name=sel>\n"; echo "จังหวัด : <font id=province><select>\n"; echo "<option value='0'>============</option> \n" ; echo "</select></font>\n";
echo "อำเภอ : <font id=amper><select>\n"; echo "<option value='0'>==== ไม่มี ====</option> \n" ; echo "</select></font>\n"; echo "ตำบล : <font id=tumbon><select>\n"; echo "<option value='0'>==== ไม่มี ====</option> \n" ; echo "</select></font>\n"; ?>
<script language=Javascript>
function Inint_AJAX() {
try { return new ActiveXObject("Msxml2.XMLHTTP"); } catch(e) {} //IE
try { return new ActiveXObject("Microsoft.XMLHTTP"); } catch(e) {} //IE
try { return new XMLHttpRequest(); } catch(e) {} //Native Javascript
alert("XMLHttpRequest not supported");
return null;
};
function dochange(src, val) {
var req = Inint_AJAX();
req.onreadystatechange = function () {
if (req.readyState==4) {
if (req.status==200) {
document.getElementById(src).innerHTML=req.responseText; //รับค่ากลับมา
}
}
};
req.open("GET", "locale.php?data="+src+"&val="+val); //สร้าง connection
req.setRequestHeader("Content-Type", "application/x-www-form-urlencoded;charset=tis-620"); // set Header
req.send(null); //ส่งค่า
}
window.onLoad=dochange('province', -1);
</script>
2. Select Province Ampher Tumbon to Show in Dropdown (locale.php)
<?
//กำหนดให้ IE อ่าน page นี้ทุกครั้ง ไม่ไปเอาจาก cache
header ("Expires: Mon, 26 Jul 1997 05:00:00 GMT");
header ("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT");
header ("Cache-Control: no-cache, must-revalidate");
header ("Pragma: no-cache");
header("content-type: application/x-javascript; charset=tis-620");
$data=$_GET['data'];
$val=$_GET['val'];
//ค่ากำหนดของ ฐานข้อมูล
$dbhost = "localhost";
$dbuser = "";
$dbpass = "";
$dbname = "test";
mysql_pconnect($dbhost,$dbuser,$dbpass) or die ("Unable to connect to MySQL server");
if ($data=='province') {
echo "<select name='province' onChange=\"dochange('amper', this.value)\">\n";
echo "<option value='0'>==== เลือก สังกัด ====</option>\n";
$result=mysql_db_query($dbname,"select loc_code,loc_abbr from location where loc_name = location_name and loc_code != '000000' and flag_disaster is null order by loc_abbr");
while(list($id, $name)=mysql_fetch_array($result)){
echo "<option value=\"$id\" >$name</option> \n" ;
}
} else if ($data=='amper') {
echo "<select name='amper' onChange=\"dochange('tumbon', this.value)\">\n";
echo "<option value='0'>======== เลือก ========</option>\n";
$val2=$val;
$val = substr($val,0,2);
$result=mysql_db_query($dbname,"SELECT loc_code, loc_abbr FROM location WHERE loc_code != '000000' and loc_code != '$val2' AND loc_code LIKE '$val%' AND flag_disaster IS NULL ORDER BY loc_code, loc_abbr ");
while(list($id, $name)=mysql_fetch_array($result)){
echo "<option value=\"$id\" >$name</option> \n" ;
}
} else if ($data=='tumbon') {
echo "<select name='tumbon' >\n";
echo "<option value='0'>======== เลือก ========</option>\n";
$val2=$val;
$val = substr($val,0,4);
$result=mysql_db_query($dbname,"SELECT loc_code, loc_abbr, loc_name, location_name FROM location WHERE loc_code != '000000' and loc_code != '$val2' AND loc_code LIKE '$val%' AND flag_disaster IS NULL ORDER BY loc_code, loc_abbr");
while(list($id, $name)=mysql_fetch_array($result)){
echo "<option value=\"$id\" >$name</option> \n" ;
}
}
echo "</select>\n";
?>



Download Source code : ajax_dropdown.rar
mirror : ajax_dropdown.rar
( Please don’t directly link to the file… thank you )
PS. In ajax-dropdown.rar file Include
for states and cities (america)
state.php
state_dropdown.php
state.sql (MySQL)
for province ampher tumon (thailand)
locale.php
locale_dropdown.php
location.sql (MySQL)


144 comments:
พี่ครับ
พี่ครับ ช่วยอธิบายเป็น Step By Step เป็นไทยด้วยได้ไหมอ่าครับ
คือแบบ งงมากๆอ่าครับ
ขอบคุณครับ
Hi, I like this script a lot, but I am having trouble with doing my own variation of a drop down box system.
Basically I'm making a simple tire search system. You search what tires would be compatible with your car by selecting three linked drop down boxes which populate from a mysql database.
Can anyone help me out ?
m2fu : you can see example tree linked drop down at "2. Select Province Ampher Tumbon to Show in Dropdown"
first box is " if ($data=='province')"
second box is " else if ($data=='amper') "
and last box is "else if ($data=='tumbon') "
$val is value send to sql query box2 and box3
peter : อยากให้อธิบายตรงไหน ถามมาเลยครับ
Hi superkeng Can I email you because I need to explain a lot...
I can't get my third drop down box to populate
mail to superkeng at gmail.com ^__^
hi.. great code... i jus have one problem.. i can get all the 3 drops down menus to populate however when i submist a form with a POST action it does not capture the value in the drop down.... any ideas?
Hi. This ajax dropdown is amazing!!
but I have a little problem with.
I use a phplib a templating system and if i use GET " req.open("GET", "?page=state&data="+src+"&val="+val);"
it include in the td the whole page :(
and if I specify it like this: " req.open("GET", "/state.php&data="+src+"&val="+val);"
don't work.
Any idea ?
Thanks
ถ้าเราต้องการ แสดงข้อมูลจากฐานเพื่อทำการแก้ไข
และใช้ ajax จังหวัด อำเภอ ตำบล เวลาโยนค่าทำอย่างไรช่วยอธิบายให้หน่อยนะคะ ตาม เมล์คะขอบคุณมา
boy1999@hotmail.com
สุดยอดมากเลยครับ เอาไปลองใช้แล้ว แต่เวลาเลือก อำเภอแล้วมีปัญหาครับ เพราะออกมาทั้งอำเภอและตำบล เมื่อเลือกจังหวัดหรือตำบลไม่มีปัญหาครับ ไม่รู้ว่าเป็นที่ ตารางหรือเปล่าครับ
อ้อ มี Email ไหมครับเพราะจะมีรายละเอียดที่จะเขียนถามยาวครับ (คือต้องอธิบายละเอียด)ครับ
ขอบคุณล่วงหน้า
inteltwin@gmail.com
Thank you for this... got it working in a few mins and was what I have been looking for for weeks.
nice works, I will use that...
รวมๆ แล้ว ก็ มาถูกทางแล้ว
อาจจะต้องแก้ไขอีกนิดหน่อย
ตรงส่วนโปรแกรม และส่วน database ที่ยังไม่สมบูรณ์ นัก
ตอนนี้ กำลังเรียงจังหวัดตามตัวอักษรอยู่
และ เพิ่มบางจังหวัดที่ตกหล่น
เช่น กระบี่ (ตอนนี้ กำลัง แก้ไขอยู่)
ยังไงก็ ขอบคุณ สำหรับ ตัวอย่างอันนี้
ก็ช่วยประหยัดเวลา ไม่ต้องทำเองไปเยอะมากเลย
Thanks for this. It is very useful but I having trouble also. I can not get the values when press submit button. I will be glad if anyone show the solution?
Great tutorial and script - only problem I am having is when viewing the dropdown lists in IE - they slide all the way to the top of the screen - any suggestions?
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How is it possible to save selected the chosen value in a list (at the change of information of form)?
can you please explain how to implement this on blogger
Tks for this. Been chasing around google for ages to find something that is simple and that works. Slick. Well done. Got it working with both dropdowns coming out of an Ingres database.
Thank you very much for this sampling of using dropdown with ajax. I've expanded it to 7, gathering information about a vehicle so that ultimately I can show a list of parts.
Where I'm a bit stuck is how to break out and go to a new page. I.e. I've collected all the info I need and now I want to go to a page where the resulting parts are displayed.
Thanks again and if anyone has some hints re breaking to a new page, thanks in advance.
Hi,
This is a nice tutorial. But I have a problem.
When you select the category1 (firstdropdown) then the category2 list shows. But when you keep change in the category1 little faster for a while and stops, the sub category stops show the result and later it stops works totally. Why ajax gets stuck when this kind of events occurs?
Hi,
Excellent script!
Can you show me how i can have the dropdowns pre loaded and options selected?
Thank you very much!
Great script!
Looks nice, but you can't download it. Anyone have it uploaded somewhere real people can download it? (I.E.: NOT those stupid, lame-assed, 'free' upload sites?)
Hi, great script, but I'm trying to create a page where both dropdowns are defaulted on page loading from a mysql database.
Any hints on how to do this would be great. I can get the values from the database, just can't get the dropdowns to take on these values when page loads.
Waw. its cool thank for sharing, and keep posting
regard'
Bali Villas
Nice tutorial!
Hi Superkeng this is great. But I am having trouble understanding the difference between the first and second script...
I mean, do I have to use both codes ? or does one replace the other? the reason I an saying this is that when I run the first code, I get two drop downs and when I run the second one, I get another drop down.
Hi!As you see, the first code creates two dropdown list, the second section dropdown will changes depending from the first list.(See the images.
----------------)
The second dropdons creates 3 dropdown lists. But the 2 codes in my opinion is a bit different. Hello,
akos
Akos, sounds like in the first code, there is no use of mysql database...am I correct?
I have a database that has state and city, I want the user to first select a state and then the list of corresponding cities will show up in the second drop down. which code am I suppose to use?
on the dropdown image you will see:
mirror : ajax_dropdown.rar
You will find state_dropdown.php the Javascript(inside), and the original empty dropdowns.
But in state.php you have to change the database connection, that will make the changing dropdowns...
Run state.sql in phpmyadmin (run the SQL command.)
Hello!
hi, this doesnt work with me, it only appears this:
"; echo ""; $result=mysql_db_query($dbname,"select loc_code,loc_abbr from location where loc_name = location_name and loc_code != '000000' and flag_disaster is null order by loc_abbr"); while(list($id, $name)=mysql_fetch_array($result)){ echo "$name \n" ; } } else if ($data=='amper') { echo "
This coderesult might comes if your server doesn't allow the short open php tags.
how to solve it? replace all < ? into < ? php
hello, jjozsi.
yes i have found some minutes ago, i was just reply when you reply. one stuff how the triple example database works? i know that the 2 dropdown works with 2 table, the triple example is working with one table and since he doesnt appear the data because its in Thai i cannot figured it out. Can you explain it please? Best Regards
I did not tried the triple dropdown yet :) Becouse i modified it to pupolate a textarea using two dropdown list, for a project/table/ --> fieldnames lister.
I would help to comment the triple dropdown, but not today.
i found one problem. Its not working on Internet Explorer, do you know why? its working just fine on firefox.
the IE give this error: "document.getElementById(...) is null and its not an object"
regards
i use this code snippet on Opera, Firefox, Internet explorer. go to http://www.phpbuilder.com/board/ and post that problem. i'm a member of that forum with lots of experts. They can help to you. i can only suggest this. Hello, akos
something similar for those AJAX inclined
http://imagecowboy.com/articles/create_ajax_menu_asp_part1.asp
Hy all :) i've chenged a little this code, to update database tables:
you can generate it here:
http://phpcode.hu/ajax_updater/
Hi,
The code works great! It's the 3rd script I try and it finally works.
I have 2 drop downs (country and region) and a button that when pressed is suppose to add a marker on my google map centered to the region. It worked before but now it does nothing.
I call this with my button: onClick="showAddress();"
And this is my function:
function showAddress() {
var countryID = document.getElementById("countries");
var country = countryID.options[countryID.selectedIndex].text;
......... (the rest of the code that creates the marker on the map)
}
When I use this in the function
alert(countryID);
I get this: [object HTMLFontElement]
What can use to access the region and country from the drop downs?
Thanks,
Brian
Hello there, i've made an ajax generator for table update, but now you can design sub dropdowns and textfields. Test it here:
http://phpcode.hu/teszt/ajax/
Video tutorial:
http://www.youtube.com/watch?v=h7AMMb4bVgY
Demo is here:
http://phpcode.hu/teszt/ajax/ajax_teszt_update.php
May i know to predefine the state and city as selected? Example, when register user using your script is work fine. But when want to update account, i need to retrieve the stored value and set the state & city as selected. How do i do this? Please help. Thanks.
if you're using php, you can change the clint side output to re-call the dropdowns with the selected state and city numbers.
http://phpcode.hu/one_click_repo/?h=331bd2a1_99
Thanks for quick reply. But the code not work for me and i've figure it out. Below is my code:
function dochange(src, val, selected) {
.
.
req.open("GET", "state.php?data="+src+"&val="+val+"&selected="+selected);
.
}
dochange('State', state_value, 0);
dochange('Area', state_value, area_value);
dochange should pass in state_value instead of area_value and need to pass selected value to php then only can set the selected area. :) Thank you.
Yes, the two values needed to embed into the javascript calls. In the original code body.onload reload the first dropdown with a value: -1
this is what you can make if you want to reload all the dropdowns.
Hello all. This ajax dropdown will be very usefull for me,
but I have a little problem with it.
If I use GET "req.open("GET", "?act=state&data="+src+"&val="+val);"
it include in my table cell the whole page,
and if I specify it like this: " req.open("GET", "?act=some_page&state.php&data="+src+"&val="+val);"
don't work.
Its highly informative. I would be visiting your blog hereafter regularly to gather valuable information.
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You need to update that poller, the best php editor is not on the list! Since the debuggers are all bad anyway, just use a good text editor that has nice printing and indenting and color coding: ie USE KATE! (comes with Ubuntu and is available free for most/all Linux distro's..)
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I used the above state.php and state_dropdown.php ..... It is only displayin a dropdoen menu but no states and cities are coming in it....
Then try to set up the server side script correctly first. The mysql connection, the tables created ,ect.
alert("Testing");
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Anyone have an up to date version of this?
Cheers
@Jase : What do you mean by: "up to date"?
If you need you can change the code to prevent MYSQL injection. Or search a newest database from countries.
I've made a JQUERY select generator for two or three dropdowns.
Here
php.hu
I just mean i find this hard to understand, im trying to impliment this myself and im having no luck. I was wondering if there was a tutorial for this instead of just source code.
It would be great if you could email me actually if you are quite good with this.
i can make a video how to install it, but you have to decide which dropdown you need.
It takes time to 'insetall' the SQL tables, maybe you have trouble around that?
oh.. nice article. I had learned something interesting with your post. thanks a lot. keep on updating.
seo tutorial
Great coding..seen others but this was the easiest to work with..took me a while to get it to work but main issues where connection to database stuff not the coding....
The only problem I have is that the third dropdown doesn't change when the first drop has changed. Anyone have any suggestions?
The third dropdown and the first aren't in connection. Just the first to the second, and the second to the third. You need to pass the value based on its value.
Gee that was a quick reply. Thanks.
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How can I make the third dropdown change when the first drop has changed.
pls give me some code.
nice works!
Hi Chris
How I did it was to create 3 functions. One like the one here, one that resets the third dropdown and one that is like the one here and also calls the third dropdown reset. Have a play and try and figure it out. Let us know if you've cracked it.
I'm sorry this is probably not the answer you want. Took me ages to figure it but have learnt from it.
I have a problem. My second dropdown values are returning empty values when sent for saving. what must be the problem
The second dropdown based on the first dropdown value, so you can troubleshoot if you save the passed value and save that into a file in PHP. I usually save the whole SQL query string i have when the dropdowns are changing, you can save into a file, and can test in PHPMYADMIN.
All the returning values in JS could displayed for test, use the alert function on the returning results.
Tum mai tueng, Tum gub chun dai
it is a great post but when i use post method then the value is show the id not value pls help me if any solution for this problem on my mail id.
rajeev.kumar6663@gmail.com
Basically this script uses HTML codes when you call the JS functions. So in the PHP file you can modify the the field names which inserted into the < option value ="$id" > $value < /option >
oh my god finally i found some one who can understand what are he talking about ..you helped me so so much thanksفيس بوك
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phpcode.hu,
you made this code to set the php variable:
function recall()
{
dochange('states',);
dochange('cities', );
}
window.onLoad=recall();
Could you tell me where to place it? Because as soon as i try to place it i lose my values in the 1st dropdown
thank you!
PS iam using the version with 2 dropboxes and i need the value of the second dropbox to be posted to the next page.
Thank you!
How to get values from selected dropdowns for insert into database ?
Great thoughts you got there, believe I may possibly try just some of it throughout my daily life.
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VÕ ĐÌNH said...
How to get values from selected dropdowns for insert into database ?
Add a form to the dropdowns, and post to a process.php file.
The code is right here:
http://phpcode.hu/one_click_repo/?h=89ce2810_135
Hello friends, you can find a code maker here with tutorial video:
http://phpcode.hu/teszt/ajax_helper/?lang=eng
With it you can easily generate unlimited linked listboxes.
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Could you explain the following two query strings?
$data=$_GET['data'];
$val=$_GET['val'];
I don't see where the data is stored or being pulled from for the 'data' and 'val'
Thanks!
it isnt, it stores it in the link so you can withdraw it from the url after the user selected and posted
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The example at: http://superkeng.freehyperspace.com/state_dropdown.php does not work.
we are not wizards, so share the source code intead of a broken url, please. There are a couple of good programming forums to get help. phpbuilder.com 4 example.
so share the source code intead of a broken url, please. There are a couple of good programming forums to get help. phpbuilder.com 4 example.
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i get ur coding for drop down menu thank u
nice tutorial, i have only one question. I would like to select multiple values in the first selectbox, and show from all those values the results in the second dropdown. Does someone know how i can do this??
many thanx in advance
Nice drop down, just I'm going to add my project. thanks
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Perfect post. Here’s a tool that lets your build your online database without programming. There is no need to hand code PHP. Cut your development time by 90% http://www.caspio.com/
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Thanks for code.. This code is in PHP but I am going to use in DNN Development. I hope it will work.
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hello I got the following error while I opening the next file
Notice: Undefined index: data in C:\xampp\htdocs\series\index3.php on line
Notice: Undefined index: val in C:\xampp\htdocs\series\index3.php on line
pls help me...
hello I got the following error while I opening the next file
Notice: Undefined index: data in C:\xampp\htdocs\series\index3.php on line
Notice: Undefined index: val in C:\xampp\htdocs\series\index3.php on line
pls help me...
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